STORM2K

First Riddle to Solve

What row of numbers comes next?

1
11
21
1211
111221
312211
13112221

chadtm80 wrote:First Riddle to Solve

What row of numbers comes next?

1
11
21
1211
111221
312211
13112221

1113213211?

Heres one for the masses.

3 men working out of town need a motel room for the night, they pull into a Days Inn and ask how much is a room for the night? the bellhop says $30 dollars. The 3 men agree to pay $10 each for the room, later the clerk realizes that the men were charged $5 dollars to much and gave the bellhop $5 to take back up to the men. The bellhop desides that he will keep $2 dollars and give each of the men back $1 dollar each.

So now the men have paid $9 dollars each for the room thats $27 dollars total and the bellhop keep $2 dollars which makes $29 dollars total (9+9+9=27+2=29). wheres the other dollar???

The next row is indeed
1113213211

Starting with the second line, every line describes the line before it. In writing, it is:
One One
Two Ones
One Two One One
etc.
etc.

Great Job Storm.. You got it a heck of alot faster then I did..


Another One: A lil eaiser I believe

A woman has 7 children, half of them are boys.
How can this be possible?

One hasn't been born yet?

therock1811 wrote:One hasn't been born yet?

thats what I was going to say

chadtm80 wrote:Another One: A lil eaiser I believe

A woman has 7 children, half of them are boys.
How can this be possible?

"Them" refers to the woman and the 7 children. Total of 8. Half of them are boys = 4. Three daughters, plus the woman = the other 4.

CaptinCrunch wrote:Heres one for the masses.

3 men working out of town need a motel room for the night, they pull into a Days Inn and ask how much is a room for the night? the bellhop says $30 dollars. The 3 men agree to pay $10 each for the room, later the clerk realizes that the men were charged $5 dollars to much and gave the bellhop $5 to take back up to the men. The bellhop desides that he will keep $2 dollars and give each of the men back $1 dollar each.

So now the men have paid $9 dollars each for the room thats $27 dollars total and the bellhop keep $2 dollars which makes $29 dollars total (9+9+9=27+2=29). wheres the other dollar???

If the hotel room was actually $25 and the overpaid $5 got split this way -- $1 to each man (for a total of $3) and $2 was kept by the bellhop ($25+$3+$2=$30). There is no extra dollar. Furthermore, each man paid $9 not for the cost of the ROOM, but for the cost of the ROOM and the THEFT by the bellhop. The cost of the room is $25. The bellhop kept $2. $25+$2=$27 $27 divided by the three men is $9, which is what each man paid. $27 + the $3 refunded to them = $30.

GalvestonDuck wrote:

CaptinCrunch wrote:Heres one for the masses.

3 men working out of town need a motel room for the night, they pull into a Days Inn and ask how much is a room for the night? the bellhop says $30 dollars. The 3 men agree to pay $10 each for the room, later the clerk realizes that the men were charged $5 dollars to much and gave the bellhop $5 to take back up to the men. The bellhop desides that he will keep $2 dollars and give each of the men back $1 dollar each.

So now the men have paid $9 dollars each for the room thats $27 dollars total and the bellhop keep $2 dollars which makes $29 dollars total (9+9+9=27+2=29). wheres the other dollar???

If the hotel room was actually $25 and the overpaid $5 got split this way -- $1 to each man (for a total of $3) and $2 was kept by the bellhop ($25+$3+$2=$30). There is no extra dollar. Furthermore, each man paid $9 not for the cost of the ROOM, but for the cost of the ROOM and the THEFT by the bellhop. The cost of the room is $25. The bellhop kept $2. $25+$2=$27 $27 divided by the three men is $9, which is what each man paid. $27 + the $3 refunded to them = $30.

very good!!:)
It took 2 hours before someone here at work got it

Thank ya!

It throws people because they try to add in the $2 for the bellhop AFTER figuring what the men paid, when in fact, part of what the men paid INCLUDES the $2.

The Big Dog wrote:

chadtm80 wrote:Another One: A lil eaiser I believe

A woman has 7 children, half of them are boys.
How can this be possible?

"Them" refers to the woman and the 7 children. Total of 8. Half of them are boys = 4. Three daughters, plus the woman = the other 4.

Sorry.. Nope.. Logical, but not the answer

chadtm80 wrote:

The Big Dog wrote:

chadtm80 wrote:Another One: A lil eaiser I believe

A woman has 7 children, half of them are boys.
How can this be possible?

"Them" refers to the woman and the 7 children. Total of 8. Half of them are boys = 4. Three daughters, plus the woman = the other 4.

Sorry.. Nope.. Logical, but not the answer

One is androgynous?!

chadtm80 wrote: Another One: A lil eaiser I believe

A woman has 7 children, half of them are boys.
How can this be possible?

So's the other half. They're ALL boys.

GalvestonDuck wrote:

chadtm80 wrote: Another One: A lil eaiser I believe

A woman has 7 children, half of them are boys.
How can this be possible?

So's the other half. They're ALL boys.

Oi! I knew I shouldn't have even opened up this thread with this hangover.

JenBayles wrote:

chadtm80 wrote:

The Big Dog wrote:

chadtm80 wrote:Another One: A lil eaiser I believe

A woman has 7 children, half of them are boys.
How can this be possible?

"Them" refers to the woman and the 7 children. Total of 8. Half of them are boys = 4. Three daughters, plus the woman = the other 4.

Sorry.. Nope.. Logical, but not the answer

One is androgynous?!

I think you mean hermaphroditic.

Or not.

GalvestonDuck wrote:

chadtm80 wrote: Another One: A lil eaiser I believe

A woman has 7 children, half of them are boys.
How can this be possible?

So's the other half. They're ALL boys.

I would agree with that Duckie.

The Big Dog wrote:

JenBayles wrote:

chadtm80 wrote:

The Big Dog wrote:

chadtm80 wrote:Another One: A lil eaiser I believe

A woman has 7 children, half of them are boys.
How can this be possible?

"Them" refers to the woman and the 7 children. Total of 8. Half of them are boys = 4. Three daughters, plus the woman = the other 4.

Sorry.. Nope.. Logical, but not the answer

One is androgynous?!

I think you mean hermaphroditic.

Or not.

Yeah! Yeah! That's it! <removes head from rear end>

GalvestonDuck wrote:

chadtm80 wrote: Another One: A lil eaiser I believe

A woman has 7 children, half of them are boys.
How can this be possible?

So's the other half. They're ALL boys.

Ding Ding Ding.. You got it Duckie.. There all boys.. There for Half of them are boys

New One:

You throw away the outside and cook the inside. Then you eat the outside and throw away the inside. What did you eat?

chadtm80 wrote: New One:

You throw away the outside and cook the inside. Then you eat the outside and throw away the inside. What did you eat?

Haggis?

No.. LOL